6x-(x-3)=2(x+1)

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Solution for 6x-(x-3)=2(x+1) equation: 



6x-(x-3)=2(x+1)

We move all terms to the left:

6x-(x-3)-(2(x+1))=0

We get rid of parentheses

6x-x-(2(x+1))+3=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

5x-(2x+2)+3=0

We get rid of parentheses

5x-2x-2+3=0

We add all the numbers together, and all the variables

3x+1=0

We move all terms containing x to the left, all other terms to the right

3x=-1

x=-1/3

x=-1/3

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