6x-(x+(3x+1)-8)=5

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Solution for 6x-(x+(3x+1)-8)=5 equation: 



6x-(x+(3x+1)-8)=5

We move all terms to the left:

6x-(x+(3x+1)-8)-(5)=0



We calculate terms in parentheses: -(x+(3x+1)-8), so:

x+(3x+1)-8

We get rid of parentheses

x+3x+1-8

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We get rid of parentheses

6x-4x+7-5=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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