6x-(3x-2)=2(x-8)

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Solution for 6x-(3x-2)=2(x-8) equation: 



6x-(3x-2)=2(x-8)

We move all terms to the left:

6x-(3x-2)-(2(x-8))=0

We get rid of parentheses

6x-3x-(2(x-8))+2=0



We calculate terms in parentheses: -(2(x-8)), so:

2(x-8)

We multiply parentheses

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

3x-(2x-16)+2=0

We get rid of parentheses

3x-2x+16+2=0

We add all the numbers together, and all the variables

x+18=0

We move all terms containing x to the left, all other terms to the right

x=-18

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