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6x-(2-2x)=-2+4(x+2)
We move all terms to the left:
6x-(2-2x)-(-2+4(x+2))=0
We add all the numbers together, and all the variables
6x-(-2x+2)-(-2+4(x+2))=0
We get rid of parentheses
6x+2x-(-2+4(x+2))-2=0
We calculate terms in parentheses: -(-2+4(x+2)), so:We add all the numbers together, and all the variables
-2+4(x+2)
determiningTheFunctionDomain 4(x+2)-2
We multiply parentheses
4x+8-2
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
8x-(4x+6)-2=0
We get rid of parentheses
8x-4x-6-2=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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