6x-(2-(3x-1)-8)=-2(x+5)+7

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Solution for 6x-(2-(3x-1)-8)=-2(x+5)+7 equation: 



6x-(2-(3x-1)-8)=-2(x+5)+7

We move all terms to the left:

6x-(2-(3x-1)-8)-(-2(x+5)+7)=0



We calculate terms in parentheses: -(2-(3x-1)-8), so:

2-(3x-1)-8

determiningTheFunctionDomain
-(3x-1)+2-8

We add all the numbers together, and all the variables

-(3x-1)-6

We get rid of parentheses

-3x+1-6

We add all the numbers together, and all the variables

-3x-5

Back to the equation:

-(-3x-5)





We calculate terms in parentheses: -(-2(x+5)+7), so:

-2(x+5)+7

We multiply parentheses

-2x-10+7

We add all the numbers together, and all the variables

-2x-3

Back to the equation:

-(-2x-3)



We get rid of parentheses

6x+3x+2x+5+3=0

We add all the numbers together, and all the variables

11x+8=0

We move all terms containing x to the left, all other terms to the right

11x=-8

x=-8/11

x=-8/11

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