6x-(1-4x)-2x=16-2(3x+5)

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Solution for 6x-(1-4x)-2x=16-2(3x+5) equation:



6x-(1-4x)-2x=16-2(3x+5)
We move all terms to the left:
6x-(1-4x)-2x-(16-2(3x+5))=0
We add all the numbers together, and all the variables
6x-(-4x+1)-2x-(16-2(3x+5))=0
We add all the numbers together, and all the variables
4x-(-4x+1)-(16-2(3x+5))=0
We get rid of parentheses
4x+4x-(16-2(3x+5))-1=0
We calculate terms in parentheses: -(16-2(3x+5)), so:
16-2(3x+5)
determiningTheFunctionDomain -2(3x+5)+16
We multiply parentheses
-6x-10+16
We add all the numbers together, and all the variables
-6x+6
Back to the equation:
-(-6x+6)
We add all the numbers together, and all the variables
8x-(-6x+6)-1=0
We get rid of parentheses
8x+6x-6-1=0
We add all the numbers together, and all the variables
14x-7=0
We move all terms containing x to the left, all other terms to the right
14x=7
x=7/14
x=1/2

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