6x+8/x-2=10

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Solution for 6x+8/x-2=10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6*x+8/x-2 = 10 // - 10

6*x+8/x-10-2 = 0

6*x^1+8*x^-1-12*x^0 = 0

(6*x^2-12*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2-12*x^1+8*x^0) = 0

x^1

6*x^2-12*x+8 = 0

6*x^2-12*x+8 = 0

DELTA = (-12)^2-(4*6*8)

DELTA = -48

DELTA < 0

x in { } 

x belongs to the empty set

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