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6x+6x+20=4(3x+5)
We move all terms to the left:
6x+6x+20-(4(3x+5))=0
We add all the numbers together, and all the variables
12x-(4(3x+5))+20=0
We calculate terms in parentheses: -(4(3x+5)), so:We get rid of parentheses
4(3x+5)
We multiply parentheses
12x+20
Back to the equation:
-(12x+20)
12x-12x-20+20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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