6x+5=(x+2)+3x-1

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Solution for 6x+5=(x+2)+3x-1 equation: 



6x+5=(x+2)+3x-1

We move all terms to the left:

6x+5-((x+2)+3x-1)=0



We calculate terms in parentheses: -((x+2)+3x-1), so:

(x+2)+3x-1

We add all the numbers together, and all the variables

3x+(x+2)-1

We get rid of parentheses

3x+x+2-1

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We get rid of parentheses

6x-4x-1+5=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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