6x+5/2=5(2-x)/3

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Solution for 6x+5/2=5(2-x)/3 equation: 



6x+5/2=5(2-x)/3

We move all terms to the left:

6x+5/2-(5(2-x)/3)=0

We add all the numbers together, and all the variables

6x-(5(-1x+2)/3)+5/2=0

We calculate fractions


6x+(-(5(-1x+2)*2)/()+()/()=0



We calculate terms in parentheses: +(-(5(-1x+2)*2)/()+()/(), so:

-(5(-1x+2)*2)/()+()/(

We add all the numbers together, and all the variables

-(5(-1x+2)*2)/()+1

We multiply all the terms by the denominator


-(5(-1x+2)*2)+1*()



We calculate terms in parentheses: -(5(-1x+2)*2), so:

5(-1x+2)*2

We multiply parentheses

-10x+20

Back to the equation:

-(-10x+20)



We add all the numbers together, and all the variables

-(-10x+20)

We get rid of parentheses

10x-20

Back to the equation:

+(10x-20)



We get rid of parentheses

6x+10x-20=0

We add all the numbers together, and all the variables

16x-20=0

We move all terms containing x to the left, all other terms to the right

16x=20

x=20/16

x=1+1/4

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