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6x+4/12x+4=0
Domain of the equation: 12x!=0We multiply all the terms by the denominator
x!=0/12
x!=0
x∈R
6x*12x+4*12x+4=0
Wy multiply elements
72x^2+48x+4=0
a = 72; b = 48; c = +4;
Δ = b2-4ac
Δ = 482-4·72·4
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-24\sqrt{2}}{2*72}=\frac{-48-24\sqrt{2}}{144} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+24\sqrt{2}}{2*72}=\frac{-48+24\sqrt{2}}{144} $
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