6x+4(x+3)=32

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Solution for 6x+4(x+3)=32 equation: 



6x+4(x+3)=32

We move all terms to the left:

6x+4(x+3)-(32)=0

We multiply parentheses

6x+4x+12-32=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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