6x+4(3x+2)=16

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Solution for 6x+4(3x+2)=16 equation: 



6x+4(3x+2)=16

We move all terms to the left:

6x+4(3x+2)-(16)=0

We multiply parentheses

6x+12x+8-16=0

We add all the numbers together, and all the variables

18x-8=0

We move all terms containing x to the left, all other terms to the right

18x=8

x=8/18

x=4/9

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