6x+3=4(x-1)+12

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Solution for 6x+3=4(x-1)+12 equation: 



6x+3=4(x-1)+12

We move all terms to the left:

6x+3-(4(x-1)+12)=0



We calculate terms in parentheses: -(4(x-1)+12), so:

4(x-1)+12

We multiply parentheses

4x-4+12

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

6x-4x-8+3=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2

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