6x+32=2(2+5x)

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Solution for 6x+32=2(2+5x) equation: 



6x+32=2(2+5x)

We move all terms to the left:

6x+32-(2(2+5x))=0

We add all the numbers together, and all the variables

6x-(2(5x+2))+32=0



We calculate terms in parentheses: -(2(5x+2)), so:

2(5x+2)

We multiply parentheses

10x+4

Back to the equation:

-(10x+4)



We get rid of parentheses

6x-10x-4+32=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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