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6x+3-2x=2(2x+1)+1
We move all terms to the left:
6x+3-2x-(2(2x+1)+1)=0
We add all the numbers together, and all the variables
4x-(2(2x+1)+1)+3=0
We calculate terms in parentheses: -(2(2x+1)+1), so:We get rid of parentheses
2(2x+1)+1
We multiply parentheses
4x+2+1
We add all the numbers together, and all the variables
4x+3
Back to the equation:
-(4x+3)
4x-4x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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