6x+3(2x-4)=63

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Solution for 6x+3(2x-4)=63 equation: 



6x+3(2x-4)=63

We move all terms to the left:

6x+3(2x-4)-(63)=0

We multiply parentheses

6x+6x-12-63=0

We add all the numbers together, and all the variables

12x-75=0

We move all terms containing x to the left, all other terms to the right

12x=75

x=75/12

x=6+1/4

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