6x+3(2x+4)=2(8x-3)

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Solution for 6x+3(2x+4)=2(8x-3) equation: 



6x+3(2x+4)=2(8x-3)

We move all terms to the left:

6x+3(2x+4)-(2(8x-3))=0

We multiply parentheses

6x+6x-(2(8x-3))+12=0



We calculate terms in parentheses: -(2(8x-3)), so:

2(8x-3)

We multiply parentheses

16x-6

Back to the equation:

-(16x-6)



We add all the numbers together, and all the variables

12x-(16x-6)+12=0

We get rid of parentheses

12x-16x+6+12=0

We add all the numbers together, and all the variables

-4x+18=0

We move all terms containing x to the left, all other terms to the right

-4x=-18

x=-18/-4

x=4+1/2

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