6x+3(1-2x)=3x+3(x+2)

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Solution for 6x+3(1-2x)=3x+3(x+2) equation: 



6x+3(1-2x)=3x+3(x+2)

We move all terms to the left:

6x+3(1-2x)-(3x+3(x+2))=0

We add all the numbers together, and all the variables

6x+3(-2x+1)-(3x+3(x+2))=0

We multiply parentheses

6x-6x-(3x+3(x+2))+3=0



We calculate terms in parentheses: -(3x+3(x+2)), so:

3x+3(x+2)

We multiply parentheses

3x+3x+6

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

-(6x+6)+3=0

We get rid of parentheses

-6x-6+3=0

We add all the numbers together, and all the variables

-6x-3=0

We move all terms containing x to the left, all other terms to the right

-6x=3

x=3/-6

x=-1/2

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