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6x+2x(x-6)=(3-1)+(6-8)
We move all terms to the left:
6x+2x(x-6)-((3-1)+(6-8))=0
We add all the numbers together, and all the variables
6x+2x(x-6)-(2+(-2))=0
We add all the numbers together, and all the variables
6x+2x(x-6)=0
We multiply parentheses
2x^2+6x-12x=0
We add all the numbers together, and all the variables
2x^2-6x=0
a = 2; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·2·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*2}=\frac{12}{4} =3 $
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