6x+2=(5x-27)+(3x+1)

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Solution for 6x+2=(5x-27)+(3x+1) equation: 



6x+2=(5x-27)+(3x+1)

We move all terms to the left:

6x+2-((5x-27)+(3x+1))=0



We calculate terms in parentheses: -((5x-27)+(3x+1)), so:

(5x-27)+(3x+1)

We get rid of parentheses

5x+3x-27+1

We add all the numbers together, and all the variables

8x-26

Back to the equation:

-(8x-26)



We get rid of parentheses

6x-8x+26+2=0

We add all the numbers together, and all the variables

-2x+28=0

We move all terms containing x to the left, all other terms to the right

-2x=-28

x=-28/-2

x=+14

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