6x+2(3x-5)=-10(-2x+1)-8x

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Solution for 6x+2(3x-5)=-10(-2x+1)-8x equation: 



6x+2(3x-5)=-10(-2x+1)-8x

We move all terms to the left:

6x+2(3x-5)-(-10(-2x+1)-8x)=0

We multiply parentheses

6x+6x-(-10(-2x+1)-8x)-10=0



We calculate terms in parentheses: -(-10(-2x+1)-8x), so:

-10(-2x+1)-8x

We add all the numbers together, and all the variables

-8x-10(-2x+1)

We multiply parentheses

-8x+20x-10

We add all the numbers together, and all the variables

12x-10

Back to the equation:

-(12x-10)



We add all the numbers together, and all the variables

12x-(12x-10)-10=0

We get rid of parentheses

12x-12x+10-10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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