6x+2(3x-1)=8(x-1)

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Solution for 6x+2(3x-1)=8(x-1) equation: 



6x+2(3x-1)=8(x-1)

We move all terms to the left:

6x+2(3x-1)-(8(x-1))=0

We multiply parentheses

6x+6x-(8(x-1))-2=0



We calculate terms in parentheses: -(8(x-1)), so:

8(x-1)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We add all the numbers together, and all the variables

12x-(8x-8)-2=0

We get rid of parentheses

12x-8x+8-2=0

We add all the numbers together, and all the variables

4x+6=0

We move all terms containing x to the left, all other terms to the right

4x=-6

x=-6/4

x=-1+1/2

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