6x+2(3x+2)=100

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Solution for 6x+2(3x+2)=100 equation: 



6x+2(3x+2)=100

We move all terms to the left:

6x+2(3x+2)-(100)=0

We multiply parentheses

6x+6x+4-100=0

We add all the numbers together, and all the variables

12x-96=0

We move all terms containing x to the left, all other terms to the right

12x=96

x=96/12

x=8

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