6x+1=5-3(3x-2)

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Solution for 6x+1=5-3(3x-2) equation: 



6x+1=5-3(3x-2)

We move all terms to the left:

6x+1-(5-3(3x-2))=0



We calculate terms in parentheses: -(5-3(3x-2)), so:

5-3(3x-2)

determiningTheFunctionDomain
-3(3x-2)+5

We multiply parentheses

-9x+6+5

We add all the numbers together, and all the variables

-9x+11

Back to the equation:

-(-9x+11)



We get rid of parentheses

6x+9x-11+1=0

We add all the numbers together, and all the variables

15x-10=0

We move all terms containing x to the left, all other terms to the right

15x=10

x=10/15

x=2/3

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