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6x+14/7x=-7
We move all terms to the left:
6x+14/7x-(-7)=0
Domain of the equation: 7x!=0We add all the numbers together, and all the variables
x!=0/7
x!=0
x∈R
6x+14/7x+7=0
We multiply all the terms by the denominator
6x*7x+7*7x+14=0
Wy multiply elements
42x^2+49x+14=0
a = 42; b = 49; c = +14;
Δ = b2-4ac
Δ = 492-4·42·14
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-7}{2*42}=\frac{-56}{84} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+7}{2*42}=\frac{-42}{84} =-1/2 $
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