6x+12/10=(16+2x)/6

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Solution for 6x+12/10=(16+2x)/6 equation: 



6x+12/10=(16+2x)/6

We move all terms to the left:

6x+12/10-((16+2x)/6)=0

We add all the numbers together, and all the variables

6x-((2x+16)/6)+12/10=0

We calculate fractions


6x+(-((2x+16)*10)/()+()/()=0



We calculate terms in parentheses: +(-((2x+16)*10)/()+()/(), so:

-((2x+16)*10)/()+()/(

We add all the numbers together, and all the variables

-((2x+16)*10)/()+1

We multiply all the terms by the denominator


-((2x+16)*10)+1*()



We calculate terms in parentheses: -((2x+16)*10), so:

(2x+16)*10

We multiply parentheses

20x+160

Back to the equation:

-(20x+160)



We add all the numbers together, and all the variables

-(20x+160)

We get rid of parentheses

-20x-160

Back to the equation:

+(-20x-160)



We get rid of parentheses

6x-20x-160=0

We add all the numbers together, and all the variables

-14x-160=0

We move all terms containing x to the left, all other terms to the right

-14x=160

x=160/-14

x=-11+3/7

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