6x+(4x+20)=(8x+44)

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Solution for 6x+(4x+20)=(8x+44) equation: 



6x+(4x+20)=(8x+44)

We move all terms to the left:

6x+(4x+20)-((8x+44))=0

We get rid of parentheses

6x+4x-((8x+44))+20=0



We calculate terms in parentheses: -((8x+44)), so:

(8x+44)

We get rid of parentheses

8x+44

Back to the equation:

-(8x+44)



We add all the numbers together, and all the variables

10x-(8x+44)+20=0

We get rid of parentheses

10x-8x-44+20=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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