6x+(3x-17)=4x+3(4x-1)

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Solution for 6x+(3x-17)=4x+3(4x-1) equation: 



6x+(3x-17)=4x+3(4x-1)

We move all terms to the left:

6x+(3x-17)-(4x+3(4x-1))=0

We get rid of parentheses

6x+3x-(4x+3(4x-1))-17=0



We calculate terms in parentheses: -(4x+3(4x-1)), so:

4x+3(4x-1)

We multiply parentheses

4x+12x-3

We add all the numbers together, and all the variables

16x-3

Back to the equation:

-(16x-3)



We add all the numbers together, and all the variables

9x-(16x-3)-17=0

We get rid of parentheses

9x-16x+3-17=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2

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