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6x(x-8)=29
We move all terms to the left:
6x(x-8)-(29)=0
We multiply parentheses
6x^2-48x-29=0
a = 6; b = -48; c = -29;
Δ = b2-4ac
Δ = -482-4·6·(-29)
Δ = 3000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3000}=\sqrt{100*30}=\sqrt{100}*\sqrt{30}=10\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-10\sqrt{30}}{2*6}=\frac{48-10\sqrt{30}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+10\sqrt{30}}{2*6}=\frac{48+10\sqrt{30}}{12} $
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