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6x(x+7)=x+47
We move all terms to the left:
6x(x+7)-(x+47)=0
We multiply parentheses
6x^2+42x-(x+47)=0
We get rid of parentheses
6x^2+42x-x-47=0
We add all the numbers together, and all the variables
6x^2+41x-47=0
a = 6; b = 41; c = -47;
Δ = b2-4ac
Δ = 412-4·6·(-47)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-53}{2*6}=\frac{-94}{12} =-7+5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+53}{2*6}=\frac{12}{12} =1 $
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