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6x(x+4)=(-11)
We move all terms to the left:
6x(x+4)-((-11))=0
We add all the numbers together, and all the variables
6x(x+4)+11=0
We multiply parentheses
6x^2+24x+11=0
a = 6; b = 24; c = +11;
Δ = b2-4ac
Δ = 242-4·6·11
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{78}}{2*6}=\frac{-24-2\sqrt{78}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{78}}{2*6}=\frac{-24+2\sqrt{78}}{12} $
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