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6x(x+3)-2=3x(2x-2)
We move all terms to the left:
6x(x+3)-2-(3x(2x-2))=0
We multiply parentheses
6x^2+18x-(3x(2x-2))-2=0
We calculate terms in parentheses: -(3x(2x-2)), so:We get rid of parentheses
3x(2x-2)
We multiply parentheses
6x^2-6x
Back to the equation:
-(6x^2-6x)
6x^2-6x^2+18x+6x-2=0
We add all the numbers together, and all the variables
24x-2=0
We move all terms containing x to the left, all other terms to the right
24x=2
x=2/24
x=1/12
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