6x(x+20)=3x(2x+40)

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Solution for 6x(x+20)=3x(2x+40) equation: 



6x(x+20)=3x(2x+40)

We move all terms to the left:

6x(x+20)-(3x(2x+40))=0

We multiply parentheses

6x^2+120x-(3x(2x+40))=0



We calculate terms in parentheses: -(3x(2x+40)), so:

3x(2x+40)

We multiply parentheses

6x^2+120x

Back to the equation:

-(6x^2+120x)



We get rid of parentheses

6x^2-6x^2+120x-120x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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