6x(5x-3)=13+6x

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Solution for 6x(5x-3)=13+6x equation:



6x(5x-3)=13+6x
We move all terms to the left:
6x(5x-3)-(13+6x)=0
We add all the numbers together, and all the variables
6x(5x-3)-(6x+13)=0
We multiply parentheses
30x^2-18x-(6x+13)=0
We get rid of parentheses
30x^2-18x-6x-13=0
We add all the numbers together, and all the variables
30x^2-24x-13=0
a = 30; b = -24; c = -13;
Δ = b2-4ac
Δ = -242-4·30·(-13)
Δ = 2136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2136}=\sqrt{4*534}=\sqrt{4}*\sqrt{534}=2\sqrt{534}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{534}}{2*30}=\frac{24-2\sqrt{534}}{60} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{534}}{2*30}=\frac{24+2\sqrt{534}}{60} $

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