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6x(3x-5)-2(4x-5)=0
We multiply parentheses
18x^2-30x-8x+10=0
We add all the numbers together, and all the variables
18x^2-38x+10=0
a = 18; b = -38; c = +10;
Δ = b2-4ac
Δ = -382-4·18·10
Δ = 724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{724}=\sqrt{4*181}=\sqrt{4}*\sqrt{181}=2\sqrt{181}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-2\sqrt{181}}{2*18}=\frac{38-2\sqrt{181}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+2\sqrt{181}}{2*18}=\frac{38+2\sqrt{181}}{36} $
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