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6x(3x-1)=60
We move all terms to the left:
6x(3x-1)-(60)=0
We multiply parentheses
18x^2-6x-60=0
a = 18; b = -6; c = -60;
Δ = b2-4ac
Δ = -62-4·18·(-60)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-66}{2*18}=\frac{-60}{36} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+66}{2*18}=\frac{72}{36} =2 $
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