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6x(3x+2)-5(3x+2)=0
We multiply parentheses
18x^2+12x-15x-10=0
We add all the numbers together, and all the variables
18x^2-3x-10=0
a = 18; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·18·(-10)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*18}=\frac{-24}{36} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*18}=\frac{30}{36} =5/6 $
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