6x(2+3x)+3x(x-4)=63

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Solution for 6x(2+3x)+3x(x-4)=63 equation: 


Simplifying
6x(2 + 3x) + 3x(x + -4) = 63
(2 * 6x + 3x * 6x) + 3x(x + -4) = 63
(12x + 18x2) + 3x(x + -4) = 63

Reorder the terms:
12x + 18x2 + 3x(-4 + x) = 63
12x + 18x2 + (-4 * 3x + x * 3x) = 63
12x + 18x2 + (-12x + 3x2) = 63

Reorder the terms:
12x + -12x + 18x2 + 3x2 = 63

Combine like terms: 12x + -12x = 0
0 + 18x2 + 3x2 = 63
18x2 + 3x2 = 63

Combine like terms: 18x2 + 3x2 = 21x2
21x2 = 63

Solving
21x2 = 63

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '21'.
x2 = 3

Simplifying
x2 = 3

Take the square root of each side:
x = {-1.732050808, 1.732050808}

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