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6x(2)-3x-45=0
We add all the numbers together, and all the variables
6x^2-3x-45=0
a = 6; b = -3; c = -45;
Δ = b2-4ac
Δ = -32-4·6·(-45)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-33}{2*6}=\frac{-30}{12} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+33}{2*6}=\frac{36}{12} =3 $
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