6x(2)+9x+5=(2x+3)(3x+2)

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Solution for 6x(2)+9x+5=(2x+3)(3x+2) equation: 



6x(2)+9x+5=(2x+3)(3x+2)

We move all terms to the left:

6x(2)+9x+5-((2x+3)(3x+2))=0

We add all the numbers together, and all the variables

6x^2+9x-((2x+3)(3x+2))+5=0

We multiply parentheses ..

6x^2-((+6x^2+4x+9x+6))+9x+5=0



We calculate terms in parentheses: -((+6x^2+4x+9x+6)), so:

(+6x^2+4x+9x+6)

We get rid of parentheses

6x^2+4x+9x+6

We add all the numbers together, and all the variables

6x^2+13x+6

Back to the equation:

-(6x^2+13x+6)



We add all the numbers together, and all the variables

6x^2+9x-(6x^2+13x+6)+5=0

We get rid of parentheses

6x^2-6x^2+9x-13x-6+5=0

We add all the numbers together, and all the variables

-4x-1=0

We move all terms containing x to the left, all other terms to the right

-4x=1

x=1/-4

x=-1/4

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