6w2+18w+12=0

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Solution for 6w2+18w+12=0 equation:



6w^2+18w+12=0
a = 6; b = 18; c = +12;
Δ = b2-4ac
Δ = 182-4·6·12
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*6}=\frac{-24}{12} =-2 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*6}=\frac{-12}{12} =-1 $

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