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6v^2+66v=72
We move all terms to the left:
6v^2+66v-(72)=0
a = 6; b = 66; c = -72;
Δ = b2-4ac
Δ = 662-4·6·(-72)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-78}{2*6}=\frac{-144}{12} =-12 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+78}{2*6}=\frac{12}{12} =1 $
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