6v-8+2(2v+3)=-4(v+1)

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Solution for 6v-8+2(2v+3)=-4(v+1) equation: 



6v-8+2(2v+3)=-4(v+1)

We move all terms to the left:

6v-8+2(2v+3)-(-4(v+1))=0

We multiply parentheses

6v+4v-(-4(v+1))+6-8=0



We calculate terms in parentheses: -(-4(v+1)), so:

-4(v+1)

We multiply parentheses

-4v-4

Back to the equation:

-(-4v-4)



We add all the numbers together, and all the variables

10v-(-4v-4)-2=0

We get rid of parentheses

10v+4v+4-2=0

We add all the numbers together, and all the variables

14v+2=0

We move all terms containing v to the left, all other terms to the right

14v=-2

v=-2/14

v=-1/7

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