6v+5v=8(v-3)-2(v+3)

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Solution for 6v+5v=8(v-3)-2(v+3) equation: 



6v+5v=8(v-3)-2(v+3)

We move all terms to the left:

6v+5v-(8(v-3)-2(v+3))=0

We add all the numbers together, and all the variables

11v-(8(v-3)-2(v+3))=0



We calculate terms in parentheses: -(8(v-3)-2(v+3)), so:

8(v-3)-2(v+3)

We multiply parentheses

8v-2v-24-6

We add all the numbers together, and all the variables

6v-30

Back to the equation:

-(6v-30)



We get rid of parentheses

11v-6v+30=0

We add all the numbers together, and all the variables

5v+30=0

We move all terms containing v to the left, all other terms to the right

5v=-30

v=-30/5

v=-6

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