6u2+24u=30

Solution for 6u2+24u=30 equation:

6u^2+24u=30

We move all terms to the left:

6u^2+24u-(30)=0

a = 6; b = 24; c = -30;
Δ = b2-4ac
Δ = 242-4·6·(-30)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*6}=\frac{-60}{12}
=-5
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*6}=\frac{12}{12}
=1
$