6u-2(1-3u)=10

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Solution for 6u-2(1-3u)=10 equation: 



6u-2(1-3u)=10

We move all terms to the left:

6u-2(1-3u)-(10)=0

We add all the numbers together, and all the variables

6u-2(-3u+1)-10=0

We multiply parentheses

6u+6u-2-10=0

We add all the numbers together, and all the variables

12u-12=0

We move all terms containing u to the left, all other terms to the right

12u=12

u=12/12

u=1

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