6u+6-2(-3u-1)=2(u-3)

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Solution for 6u+6-2(-3u-1)=2(u-3) equation: 



6u+6-2(-3u-1)=2(u-3)

We move all terms to the left:

6u+6-2(-3u-1)-(2(u-3))=0

We multiply parentheses

6u+6u-(2(u-3))+2+6=0



We calculate terms in parentheses: -(2(u-3)), so:

2(u-3)

We multiply parentheses

2u-6

Back to the equation:

-(2u-6)



We add all the numbers together, and all the variables

12u-(2u-6)+8=0

We get rid of parentheses

12u-2u+6+8=0

We add all the numbers together, and all the variables

10u+14=0

We move all terms containing u to the left, all other terms to the right

10u=-14

u=-14/10

u=-1+2/5

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