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6t=8(t-3/4)
We move all terms to the left:
6t-(8(t-3/4))=0
We add all the numbers together, and all the variables
6t-(8(+t-3/4))=0
We multiply all the terms by the denominator
6t*4))-(8(+t-3=0
We add all the numbers together, and all the variables
t+6t*4))-(8(-3=0
Wy multiply elements
24t^2+t-3=0
a = 24; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·24·(-3)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-17}{2*24}=\frac{-18}{48} =-3/8 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+17}{2*24}=\frac{16}{48} =1/3 $
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