6t2=25t=9

Solution for 6t2=25t=9 equation:

6t^2=25t=9

We move all terms to the left:

6t^2-(25t)=0

a = 6; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·6·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*6}=\frac{0}{12}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*6}=\frac{50}{12}
=4+1/6
$